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Q. Carboxylic acids readily dissolve in aqueous sodium bicarbonate, liberating carbon dioxide. Which one of the following statement is correct?

Equilibrium

Solution:

$R COOH + NaHCO _{3} \rightleftharpoons R COONa + H _{2} O + CO _{2}$
or $ R COOH + HCO _{3}^{-} \rightleftharpoons R RCO ^{-}+ H _{2} O + CO _{2}$
conjugate base, $R COO ^{-}$is more stable than the free carboxylic acid.
That's why, equilibrium shifts in forward direction. Thus, statement (c) is correct.