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Q. Carbon occurs in nature as a mixture of $C-12$ and $C-13$. The average atomic mass of carbon is $12.011$ What is the percentage abundance of $C-12$ in nature.

Some Basic Concepts of Chemistry

Solution:

Let $x$ be the percentage abundance of $C-12$; then
$(100 - x)$ will be the percentage abundance of $C-13$.
$\therefore \frac{12x}{100} + \frac{13(100 - x)}{100} = 12.011$
$12x + 1300 - 13x = 1201 .1 $
$\Rightarrow x = 98.9$
$\therefore $ Abundance of $C-12 = 98.9\%$