Question

Calculation the maximum work done in expanding $ 16 \,g $ of oxygen at $ 300\, K $ and occupying a volume of $ 5 \,dm^3 $ isothermally until volume becomes $ 25\, dm^3 $ .

• A. $ - 2.01 \times 10^3\,J $
• B. $ + 2.01 \times 10^3\, J $
• C. $ 2.01\, J $
• D. $ 2.01 \times 10^3 \,kJ $

Answer 1

Answer: (A)

Word done for isothermal expansion,
$W=-2.303 nRT log\frac{V_{f}}{V_{i}}$
$=-2.303\times\frac{16}{32}\times8.314\times300\,\log \left(\frac{25}{5}\right)$
$=-2007.49\,J$
$=-2.01\times10^{3}\,J$