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  4. Calculate the work done when 2 moles of hydrogen expand isothermally and reversibly at 27°C from 15 to 50 litres.

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Q. Calculate the work done when $2$ moles of hydrogen expand isothermally and reversibly at $27^{\circ}C$ from $15$ to $50$ litres.

Thermodynamics

Solution:

$W=-2.303 \,nRT\, log \frac{V_{2}}{V_{1}}$
$=-2.303\times2\times2\times300 \,log \frac{50}{15}$
$=-2763.6\left(log \,10-log \,3\right)$
$=-2763.6\left(1-0.4771\right)$
$=-2763.6\times0.5229=-1445\, cal$