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Q. Calculate the work done in taking a charge $-2 \times 10^{-9} \,C$ from $A$ to $B$ via $C$ (in diagram)Physics Question Image

Electrostatic Potential and Capacitance

Solution:

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$V_{A}=\frac{9 \times 10^{9} \times 8 \times 10^{-3}}{3 \times 10^{-2}}=24 \times 10^{8} V$
$V_{B}=\frac{9 \times 10^{9} \times 8 \times 10^{-3}}{4 \times 10^{-2}}=18 \times 10^{8} V$
$\Delta W=-2 \times 10^{-9}\left(-6 \times 10^{8}\right)$
$\Delta W=12 \times 10^{-1}\, J$
$\Delta W=1.2\, J$