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  4. Calculate the work done during isothermal expansion of one mole of an ideal gas from 10 atm to 1 atm at 300 K

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Q. Calculate the work done during isothermal expansion of one mole of an ideal gas from 10 atm to 1 atm at $300 \, K$

NTA AbhyasNTA Abhyas 2022

Solution:

Given that
$P_{1}=10atm$ ,
$P_{2}=1atm$ ,
$T=300K$ ,
$n=1$
$R=8.314J/K/mol$
Now, by using
$W=2.303nRTlog_{10}\frac{P_{2}}{P_{1}}$
$=2.303\times 1\times 8.314\times 300log_{10}\frac{1}{10}$
$W= -5744.1Joule$