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Q.
Calculate the work done by the gas in the state diagram shown.
Thermodynamics
Solution:
Work done $=$ Area under the $P-V$ curve
$W=(80\, kPa )\left(250 \times 10^{-6}\right) k t\, 1 / 2=10\, J$
Since the arrow is anticlockwise,
$\therefore $ Work done $=-10\, J$
