Question

Calculate the weight of metal deposited when a current of $15$ ampere with $75\%$ current efficiency is passed through the cell for $2$ hours. (Electrochemical equivalent of metal $= 4 \times 10^{-4}$)

• A. $32.4\, g$
• B. $43.2\, g$
• C. $57.6\, g$
• D. $16.2\, g$

Answer 1

Answer: (A)

Applying, $W = Z \times I \times t$
$W =?, Z =4 \times^{-4}; I=15 \times \frac{75}{100} = \frac{45}{4}$
$t =2\, hr$. $=2 \times 3600\, sec$
$W =4 \times 10^{-4} \times \frac{45}{4} \times 2 \times 3600 = 32.4\,g$