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Q. Calculate the value of equilibrium constant when 2 moles of $PCl_{5}$ is heated in a closed vessel of 2 litre capacity. At equilibrium, 40% of $PCl_{5}$ is dissociated into $PCl_{3}$ and $Cl_{2}$ .

NTA AbhyasNTA Abhyas 2020Equilibrium

Solution:

Solution

Volume of container = $2 \, litre$ .

$K_{c}=\frac{\frac{2 \times 40}{100 \times 2} \times \frac{2 \times 40}{100 \times 2}}{\frac{2 \times 60}{100 \times 2}}=0.266$