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Q. Calculate the power factor of the circuit shown in figure
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Resistance of the circuit,
$R=R_{1}+R_{2}=40 \, \Omega+40 \, \Omega=80 \, \Omega$
Impedance of the circuit,
$Z=\sqrt{R^{2} + \left(X_{L} - X_{C}\right)^{2}}=\sqrt{\left(80\right)^{2} + \left(100 - 40\right)^{2}}$
$=\sqrt{\left(80\right)^{2} + \left(60\right)^{2}}=100 \, \Omega$
Power factor, $cos \phi=\frac{R}{Z}=\frac{80}{100}=0.8 \, $