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Q. Calculate the $pOH$ of a solution at $25^{\circ} C$ that contains $1 \times 10^{-10} M$ of hydronium ion.

AIPMTAIPMT 2007Equilibrium

Solution:

$ [H_3O^+] = [H^+] = 10^{-10} $
$ pH + pOH = 14 $
$ pH = - \log [H^+] $
$ pH = - \log [10^{-10}] $
$ pH = 10 $
$ pOH + 10 = 14 $
$ pOH = 14 - 10 = 4 $