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Q.
Calculate the molarity of pure water $(d = 1 g/L)$
Solutions
Solution:
Consider 1000 mL of water
Mass of 1000 mL of water $=1000\times 1=1000$ grams
Number of moles of water $=\frac{1000}{18}=55.5$
Molarity $= \frac{text{No. of moles of water}}{\text{Volume in litre}} $
$=\frac{55.5}{1}$
$=55.5\,M$