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  4. Calculate the molal depression constant of a solvent which has freezing point 16.6° C and latent heat of fusion 180.75 J / g.

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Q. Calculate the molal depression constant of a solvent which has freezing point $16.6^{\circ} C$ and latent heat of fusion $180.75\, J / g$.

ManipalManipal 2015Solutions

Solution:

Given,
$T_{ f } =273+16.6=289.6\, K$
$L_{f} =180.75\, J / g$
$R =8.314\, J / K / mol$
$\therefore K_{f} =\frac{K_{f}=?}{1000 \times L_{f}}=\frac{8.314 \times(289.6)^{2}}{1000 \times 180.76}$
$\therefore K_{f} =3.86$