Question

Calculate the maximum percentage error in the measurement of area of a rectangular plate whose length is $\left(\right.2 \, \pm \, 0.02\left.\right) \, cm$ and width is $\left(\right.1 \, \pm \, 0.01\left.\right) \, cm$ .

• A. $1\%$
• B. $2\%$
• C. $3\%$
• D. $5\%$

Answer 1

Answer: (B)

$A=lb$
$\frac{\Delta A}{A}\times 100=\frac{\Delta l}{l}\times 100+\frac{\Delta b}{b}\times 100$
On substituting the values, we get percentage error as 2%.