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  4. Calculate the mass of anhydrous Na2CO3 required to prepare 250 ml of 0.25 M solution.

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Q. Calculate the mass of anhydrous $Na_{2}CO_{3}$ required to prepare $250$ $ml$ of $0.25$ $M$ solution.

NTA AbhyasNTA Abhyas 2022

Solution:

Molarity of solution is given by $M=\frac{w}{m \times V \left(\right. l \left.\right)}$ ;
Hence, $0.25=\frac{w}{106 \times 0.25}$ ; $w=6.625$ $g$