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  4. Calculate the kinetic energy of the electron having wavelength 1 nm.

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Q. Calculate the kinetic energy of the electron having wavelength 1 nm.

AIIMSAIIMS 2012Dual Nature of Radiation and Matter

Solution:

de broglie wavelength,
$\lambda=\frac{h}{\sqrt{2mk}}$
or $\, k=\frac{h^{2}}{2m\lambda^{2}}$
$\quad\quad=\frac{\left(6.67\times10^{-34}\right)^{2}}{2\times9.1\times10^{-31}\left(1\times10^{-9}\right)^{2}}=1.5 eV.$