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Q.
Calculate the heat absorbed by a system in going through the cyclic process shown in diagram.
NTA AbhyasNTA Abhyas 2020Thermodynamics
Solution:
The cycle i clockwise; thus net work done by the gas. As in a cyclic process no change in internal energy takes place, heat supplied is equal to the work done by the gas in one complete cycle. So in this case heat supplied to the gas is given as
Q = work done by the gas, W
= area of ellipse
$= \pi \text{ab}$
where a and b are semi-major and semi-minor axes of the ellipse, respectively, which are given from the diagram as
a = 1.0 x 105 N/m and b = 100 x 10-6 m3
Thus area of ellipse is
$\text{Q} = \text{W} = \pi \times \text{1.0} \times 1 0^{5} \times 1 0 0 \times 1 0^{- 6}$
$= \text{3.14} \times 1 0 = \text{31.4 J}$
