1. Tardigrade
  2. Question
  3. Chemistry
  4. Calculate the equivalent weight of KHC 2 O 4 when it is neutralised by KOH.

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Calculate the equivalent weight of $KHC _{2} O _{4}$ when it is neutralised by KOH.

Redox Reactions

Solution:

$KHC _{2} O _{4} \rightleftharpoons K ^{+}+ HC _{2} O _{4}^{-} \rightleftharpoons H ^{+}+ C _{2} O _{4}^{2-}$

$KOH \rightleftharpoons K ^{+}+ OH ^{-}$

There is one replaceable $H$ in $KHC _{2} O _{4},$ so its $n$ - factor is

1. Its eq. wt $=\frac{128}{1}=128$.