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Q. Calculate the entropy change in melting $1$ mole of ice at $273K$, $\Delta H^{\circ}_{f}=6.025\, kJ/mole-$

VITEEEVITEEE 2019

Solution:

$\Delta S_{r}=\frac{\Delta H_{f}}{T}=\frac{6025\,J\,mol^{-1}}{273K}=22.1\,JK^{-1}\,mol^{-1}$