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Q. Calculate the energy of a photon of frequency $6 \times 10^{14}$ Hz in electron volt:

Dual Nature of Radiation and Matter

Solution:

$E=h v$
$E =6.6 \times 10^{-34} \times 6 \times 10^{14}$
$=\frac{6.6 \times 6 \times 10^{-20}}{1.6 \times 10^{-19}} eV E =2.47 eV$