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Q. Calculate the change in entropy when two gram atoms of aluminium is heated from $25^°C$ to $600^°C$. The atomic heat capacity of aluminium is given by $C_p = 5.006 + 0.0026 \,T\, cal/deg$.

Thermodynamics

Solution:

The process takes place at constant pressure. Hence, $ΔQ = C_p ΔT$
and $\Delta S=\int^{T_{2}}_{T_1} \frac{nC_{p}\,dT}{T}=2 \int^{873}_{298} \left(\frac{5.006}{T}+0.0026\right)dT$
$=2\left[5.006\,ln \frac{873}{298}+0.0026\left(873-298\right)\right]$
$=2\left[5.381+1.495\right]=13.75\,cal/deg$ or $13.75\, eu$