Question

Calculate the angular momentum of a particle of mass $5 \,mg$ revolving about a circle of radius $60\, cm$ with a speed of $2\, km / s$

• A. $1 \times 10^{-3} kgm ^{2} \,s^{-1}$
• B. $4 \times 10^{-3} kgm ^{2} \,s^{-1}$
• C. $6 \times 10^{-3} kgm ^{2} s^{-1}$
• D. $6 \times 10^{-4} kgm ^{2} \,s^{-1}$

Answer 1

Answer: (C)

$L =m v r=5 \times 10^{-6} \times 2 \times 10^{3} \times 60 \times 10^{-2}$
$=6 \times 10^{-3} kg m ^{2} s ^{-1} $