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  4. Calculate the amount of Ni needed in the Mond’s process given below Ni + 4CO → Ni(CO)4 If CO used in this process is obtained through a process, in which 6 g of carbon is mixed with 44 g CO2.

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Q. Calculate the amount of $Ni$ needed in the Mond’s process given below
$Ni + 4CO \to Ni(CO)_4$
If $CO$ used in this process is obtained through a process, in which $6\, g$ of carbon is mixed with $44 \,g \,CO_2$.

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Solution:

$\underset{\text{Given moles}}{} \,\,\underset{(\frac{6}{12}) = 0.5}{C \,\,+} \underset{(\frac{44}{44}) = 1}{CO_2 \to } 2CO$
So $C$ is limiting reagent
$\therefore CO$ formed $= 1$ mole
Now moles of $Ni$ need to react with $1$ mole of $CO$ are
$ \frac {1}{4} \times 58.7 = 14.675\,g$