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  4. Calculate molar conductivity of 0.15 M solution of KCl at 298 K if its conductivity is 0.0152 S cm -1 :

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Q. Calculate molar conductivity of $0.15 M$ solution of $KCl$ at $298 K$ if its conductivity is $0.0152 \,S \,cm ^{-1}$ :

Electrochemistry

Solution:

$\Lambda_{ m }=\frac{ K \times 1000}{ M }=\frac{0.0152 \times 1000}{0.15}$

$=101 \Omega^{-1} cm ^{2} mol ^{-1}$