Question

Calculate $\Lambda_{ HOAc }^{\infty}$ using appropriate molar conductances of the electrolytes listed above at infinite dilution in $H _{2} O$ at $25^{\circ} C$

• A. $217.5$
• B. $390.7$
• C. $552.7$
• D. $5172$

Answer 1

Answer: (B)

$\Lambda_{ HCl }^{\infty}=426.2$
(i) $ \Lambda_{ AcONa }^{\infty}=91.0$
(ii) $\Lambda_{ NaCl }^{\infty}=126.5$
(iii) $\Lambda_{ AcOH }^{\infty}=( i )+( ii)-(iii) $
$=[426.2+91.0-126.5]=390.7$