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Q. Calculate charge on capacitor in steady state.Physics Question Image

AIIMSAIIMS 2019Electrostatic Potential and Capacitance

Solution:

$i=\frac{9}{27\times10^{3}}$
$V_{c}=15\times10^{3}\times\frac{9}{27\times 10^{3}}$
$q=9\times10^{-6}\times\frac{15}{3}$
$q=45\times10^{-6}C$
$q=45 \mu C$