Question

Calcium imide on hydrolysis gives gas $B$ which on oxidation by bleaching powder gives gas $C$ . Gas $C$ on reaction with magnesium give compound $D$ which on hydrolysis gives again gas $B$ . Identify $B$ , $C$ and $D$ respectively.

• A. $NH_{3},N_{2},Mg_{3}N_{2}$
• B. $N_{2},NH_{3},MgNH$
• C. $N _{2}, N _{2} O _{5}, Mg \left( NO _{3}\right)_{2}$
• D. $NH _{3}, NO _{2}, Mg \left( NO _{2}\right)_{2}$

Answer 1

Answer: (A)

Here $B, C$ and $D$ are $NH_{3},N_{2}$ and $Mg_{3}N_{2}$ respectively
$Ca(NH)+2H_{2}O \rightarrow Ca(OH)_{2}+\underset{( B )}{N H_{3} \left(\right. g \left.\right)}$
$\underset{( B )}{2 N H_{3}}+3CaOCl_{2} \rightarrow \underset{(C)}{N_{2} (g )}+3CaCl_{2}+3H_{2}O$
$\underset{(C )}{N_{2} ( g )}+3Mg \rightarrow \underset{( D )}{M g_{3} N_{2}}$
$\underset{( D )}{M g_{3} N_{2}}+6H_{2}O \rightarrow 3Mg(OH)_{2}+\underset{(B )}{2 N H_{3}}$