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  4. Ca2B6O11+2Na2CO3 → X+2CaCO3+2NaBO2 The compound X in the above reaction is

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Q. $Ca_{2}B_{6}O_{11}+2Na_{2}CO_{3} \to X+2CaCO_{3}+2NaBO_{2}$ The compound $X$ in the above reaction is

The p-Block Elements

Solution:

$\underset{\text{Colemanite}}{{Ca_{2}B_{6}O_{11}}}+2Na_{2}CO_{3} \to \underset{\text{(X) (Borax)}}{{Na_{2}B_{4}O_{7}}}+2NaBO_{2}+2CaCO_{3}$