Tardigrade
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Mathematics
C is a curve defined by the parametric equation x=t2 and y=t3-3 t. The equation of the tangent line to this curve at (4,2) is
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Q. $C$ is a curve defined by the parametric equation $x=t^2$ and $y=t^3-3 t$. The equation of the tangent line to this curve at $(4,2)$ is
Application of Derivatives
A
$y=15 x-58$
B
$y=2$
C
$y=x-2$
D
$y=\frac{9 x}{4}-7$
Solution:
Slope $M =\frac{ dy }{ dx }=\frac{ dy / dt }{ dx / dt }$
$M =\frac{3 t ^2-3}{2 t } \text { at } t =2$
$M =\frac{9}{4} $
Equation of tangent at $(4,2) \cdot M=\frac{9}{4}$
$(y-2)=\frac{9}{4}(x-4) \Rightarrow y=\frac{9}{4} x-7$