Question

$ CH_3COOH \ce{->[LiAlH_4]} A + CH_3COOH \ce{->[H_3O^+]}B + H_2O$
In the above reactions A and B respectively are

• A. $ C{{H}_{3}}COO{{C}_{2}}{{H}_{5}},{{C}_{2}}{{H}_{5}}PH $
• B. $ C{{H}_{3}}CHO,{{C}_{2}}{{H}_{5}}OH $
• C. $ {{C}_{2}}{{H}_{5}}OH,C{{H}_{3}}CHO $
• D. $ {{C}_{2}}{{H}_{5}}OH,C{{H}_{3}}COO{{C}_{2}}{{H}_{5}} $

Answer 1

Answer: (D)

$CH_3COOH + 4H \ce{->[LiAlH_4]}\underset{(A)}{CH_3CH_2OH} + H_2O$
$\underset{(A)}{CH_3CH_2OH} + CH_3COOH \ce{->[H_3O^+]} \underset{(B)}{CH_3COOC_2H_5} + H_2O$