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  4. (C H3)2C=CHCOCH3 can be oxidized to (C H3)2C=CHCOOH by

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Q. $\left(C H_{3}\right)_{2}C=CHCOCH_{3}$ can be oxidized to $\left(C H_{3}\right)_{2}C=CHCOOH$ by

NTA AbhyasNTA Abhyas 2020Aldehydes Ketones and Carboxylic Acids

Solution:

$\left(C H_{3}\right)_{2}C=CHCOCH_{3}$ is a methyl ketone and therefore, it can be easily oxidized to $\left(C H_{3}\right)_{2}CCHCOOH$ by haloform or iodoform reaction (NaOI).

$\left( CH _{3}\right)_{2} C = CHCOCH _{3} \stackrel{ NaOI }{\longrightarrow }\left( CH _{3}\right)_{2} C = CHCOCI _{3} \stackrel{ NaOH }{\longrightarrow }$ $CHI _{3}+\left( CH _{3}\right)_{2} C = CHCOONa \rightarrow\left( CH _{3}\right)_{2} C = CHCOOH$

Chromic acid and $KMnO_{4}$ , being strong oxidizing agents, will also attack the multiple bond and cause the cleavage giving the mixture of carboxylic acids.