Question

$C_6H_6NH_2 \xrightarrow[{0-5^{\circ}C}] {NaNO_{2}/HCl}X \xrightarrow[{CH_2O}]{HNO_{2} Y +N_2 +HCl}$
$X$ and $Y$ are respectively

• A. $C_6H_5 - N = N - C_6H_5, C_6H_5N_{2}^{\oplus}CI^{\ominus}$
• B. $C_6H_5N_{2}^{\oplus}CI^{\ominus},C_6H_5 - N = N - C_6H_5$
• C. $C_6H_5N_{2}^{\oplus}CI^{\ominus},C_6H_5NO_2$
• D. $C_6H_5NO_2,C_6H_6$

Answer 1

Answer: (C)

Correct answer is (c) $C_6H_5N_{2}^{\oplus}CI^{\ominus},C_6H_5NO_2$