Question

$ {{C}_{6}}{{H}_{6}}+C{{l}_{2}}(excess)\frac{Anhy.AlC{{l}_{3}}}{dark,cold}P $ Product, P is

• A. $ {{C}_{6}}{{H}_{5}}Cl $
• B. $ {{C}_{6}}{{H}_{4}}C{{l}_{2}} $
• C. $ {{C}_{6}}{{H}_{6}}C{{l}_{6}} $
• D. $ {{C}_{6}}C{{l}_{6}} $

Answer 1

Answer: (D)

Benzene on treatment with excess of chlorine in the presence of anhydrous $ \text{AlC}{{\text{l}}_{\text{3}}} $ in dark yields hexachlorobenzene.