Question

$C_{6}H_{5}OH+CHCl_{3}+NaOH \rightarrow $ Salicylaldehyde the electrophile involved in the above reaction is.

• A. Dichloromethyl cation $\left(C H C l_{2} \, \right)$
• B. Dichlorocarbene $\left( : C C l_{2}\right)$
• C. Trichloromethyl anion $\bar{C}Cl_{3}$
• D. Formyl cation $\left(C H O\right)$

Answer 1

Answer: (B)

The alpha elimination reaction takes place between chloroform and sodium hydroxide.
$CHCl_{3}+NaOH \rightarrow :CCl_{2}+NaCl+H_{2}O$
The above reaction of formation of dichlorocarbene is the first step of the Riemer Tiemann reaction.