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  4. C6H5-CH=CHCHO xrightarrowX C6H5CH=CHCH2OH In the above sequence X can be:

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Q. $ {{C}_{6}}{{H}_{5}}-CH=CHCHO\xrightarrow{X} $ $ {{C}_{6}}{{H}_{5}}CH=CHC{{H}_{2}}OH $ In the above sequence X can be:

VMMC MedicalVMMC Medical 2006

Solution:

$ \text{NaB}{{\text{H}}_{\text{4}}} $ and $ \text{LiAl}{{\text{H}}_{\text{4}}} $ attacks only carbonyl group and reduce it into alcohol group. They do not attack on double bond. $ \underset{\text{Cinnamic}\,\text{aldehyde}}{\mathop{{{C}_{6}}{{H}_{5}}-CH=CHCHO}}\,\xrightarrow{\text{NaB}{{\text{H}}_{\text{4}}}} $ $ \underset{\text{Cinnamic}\,\text{alcohol}}{\mathop{{{C}_{6}}{{H}_{5}}=CH.C{{H}_{2}}OH}}\, $