1. Tardigrade
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  3. Chemistry
  4. C 6 H 12(A) has chirality but on hydrogenation (A) is converted into C 6 H 14(B) in which chirality disappears. Hence (A) is

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Q. $C _{6} H _{12}(A)$ has chirality but on hydrogenation $(A)$ is converted into $C _{6} H _{14}(B)$ in which chirality disappears. Hence $(A)$ is

Hydrocarbons

Solution:

Correct answer is (a) 3-methyl-1-pentene

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