Question

$C_{2}H_{5}I$ and $Ag_{2}O$ reacts to produce:

• A. $C_{2}H_{6}$
• B. $C_{2}H_{5}-C_{2}H_{5}$
• C. $C_{2}H_{5}-O-C_{2}H_{5}$
• D. $C_{2}H_{5}-CH_{3}$

Answer 1

Answer: (C)

$C _{2} H _{5} I$ and $Ag _{2} O$ reacts as below
$2 C _{2} H _{5} I + Ag _{2} O \longrightarrow \underset{\text{Ether}}{C _{2} H _{5} OC _{2} H _{5}+ I _{2}} +2 Ag$
Thus, $C _{2} H _{5}- O - C _{2} H _{5}$ is produced.