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Q. Bullets of mass $0.03\, kg$ each hit a plate at the rate of $200$ bullets per second with a velocity of $50\, m\, s ^{-1}$ and reflect back with a velocity of $30\, m\, s ^{-1}$. The average force (in newton) acting on the plate is

Laws of Motion

Solution:

Change in momentum of one bullet
$=m(v-u)=0.03 \times\{50-(-30)\}=2.4 kg m s ^{-1}$
Average force $=$ rate of change of momentum of $200$ bullets
$=200 \times 2.4=480 N$