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Physics
Brewster's angle in terms of refractive index (n) of the medium
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Q. Brewster's angle in terms of refractive index $(n)$ of the medium
AFMC
AFMC 2007
Wave Optics
A
$\tan^{-1}\,\sqrt{n} $
17%
B
$\sin^{-1}\,n $
9%
C
$\sin^{-1}\,\sqrt{n} $
8%
D
$\tan^{-1}\,n $
66%
Solution:
Refractive index of a medium $n=\tan i_{p}$
where $i_{p}=$ Brewster's angle
$\Rightarrow i_{p}=\tan ^{-1} n$