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Q. Brewster angle for air to water transition is (refractive index of water is $\frac{4}{3}$ )

Wave Optics

Solution:

Brewster's angle is given by $\tan ^{-1} \mu=\tan ^{-1} \frac{4}{3}$ which is also written as $\cot ^{-1} \frac{3}{4}$