1. Tardigrade
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  3. Chemistry
  4. Both oxidation and reduction takes place in :

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Q. Both oxidation and reduction takes place in :

Redox Reactions

Solution:

In the reaction :
$H_2 + Br_2 \rightarrow 2HBr$
Oxidation number of $H$ in $H_2$ is zero whereas its value is $+1$ in $HBr$ ; similarly oxidation number of $Br$ in $Br_2$ is zero where as its value is $-1$ in $HBr$. So, here $H$ is oxidised and $Br$ reduced. In all other reactions, there in no change in the oxidation number of any element.