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Chemistry
Boron is unable to form BF 63 because of
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Q. Boron is unable to form $BF _{6}^{3}$ because of
J & K CET
J & K CET 2012
The p-Block Elements
A
high electronegativity of boron
B
high electronegativity of fluorine
C
lack of d-orbitals in boron
D
less difference in electronegativity between B and F
Solution:
Due to lack of d-orbitals in $B$, it is unable to form $BF _{6}^{3-}$ complex ion.