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Q. Boron has two stable isotopes, $^{10}B (19)$% and $^{11}B (81)$%. Average atomic weight for boron in the periodic table is

Structure of Atom

Solution:

Average atomic mass
$= \frac{R.A.\left(1\right) \times M.No + R.A.\left(2\right) \times M.No.}{R.A.\left(1\right) + R.A.\left(2\right) }$
where R.A. = relative abundance
M.No = Mass number
$ = \frac{19 \times10 + 81 \times11}{100} = 10.81 $