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Q. Borazole is obtained by reacting $B_{2}H_{6}$ with:

The p-Block Elements

Solution:

$3\underset{1 : 2}{B_{2}B_{6}+6NH_{3}} \xrightarrow{823-527\, K} 2B_{3}N_{3} H_{6}$ (Borazine) $+12H_{2}$