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  4. Borazine B 3 N 3 H 6(A) is converted into disubstituted product B 3 N 3 H 4 X2(B). Number of isomers of B would be

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Q. Borazine $B _3 N _3 H _6(A)$ is converted into disubstituted product $B _3 N _3 H _4 X_2(B)$. Number of isomers of $B$ would be

The p-Block Elements

Solution:

Correct answer is (b) 4

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