Q. Bond order of $O_2, O_2^+, O_2^-$ and $O_2^{2-}$ is in order
Chemical Bonding and Molecular Structure
Solution:
Electrons
Bond order
$O_2$
16
2.0
$O_2^+$
15
2.5
$O_2^-$
17
1.5
$O_2^{2-}$
18
1.0
Thus, BO is in order
$O_2^{2-} < O_2^- < O_2 < O_2^+$
| Electrons | Bond order | |
|---|---|---|
| $O_2$ | 16 | 2.0 |
| $O_2^+$ | 15 | 2.5 |
| $O_2^-$ | 17 | 1.5 |
| $O_2^{2-}$ | 18 | 1.0 |