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Q. Bond order of $Be_{2}^{+}$ is $x$ , then what is the value of $2x$ :

NTA AbhyasNTA Abhyas 2022

Solution:

$Be_{2}^{+}:\sigma 1^{2}\sigma ^{\star}1s^{2}\sigma 2s^{2}\sigma ^{\star}2s^{1}$
$B.O.=\frac{1}{2}\left[\right.4-3\left]\right.=0.5$
$\Rightarrow 2x=1$