1. Tardigrade
  2. Question
  3. Chemistry
  4. Bond energy of Br 2 is 194 kJ mol -1 . If the minimum wave number of photons required to break this bond is given as X × 106 m -1, then the value of X will be (h=6.62 × 10-34 Js , c=3 × 108 m / s )

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Q. Bond energy of $Br _{2}$ is $194\, kJ\, mol ^{-1} .$ If the minimum wave number of photons required to break this bond is given as $X \times 10^{6} m ^{-1}$, then the value of $X$ will be
$\left(h=6.62 \times 10^{-34} Js , c=3 \times 10^{8} m / s \right)$

Structure of Atom

Solution:

$\frac{h c}{\lambda} \times N_{A}=194 \times 10^{3}$
$\frac{1}{\lambda}=\frac{194 \times 10^{3}}{6.63 \times 10^{-34} \times 10^{8} \times 6 \times 10^{23}}$
$\simeq 1.62 \times 10^{6} m ^{-1}$