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  3. Chemistry
  4. Bond angle of 109° 28' is found in :

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Q. Bond angle of $109^{\circ} 28'$ is found in :

AIEEEAIEEE 2002

Solution:

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$109^{\circ} 28'$, it means pure regular tetrahedral.
(a) $NH_3\, sp^3$ pyramidal
(b) $H_2O\,sp^3$ bent
(c) $CH_5^+$
(d)$NH_4^+\,sp^3$ tetrahedral