Question

Bond angle in $H_2O\, (104.5^{\circ})$ is higher than the bond angle of $H_2S\, (92.1^{\circ})$. The difference is due to

• A. $O$ is diatomic and $S$ is tetra-atomic
• B. difference in electronegativity of $S$ and $O$
• C. difference in oxidation states of $S$ and $O$
• D. difference in shapes of hybrid orbitals of $S$ and $O$

Answer 1

Answer: (B)

Correct answer is (b) difference in electronegativity of $S$ and $O$